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Revision guide · IGCSE

IGCSE Maths area, volume and surface area: sectors, cones, spheres and frustums

Mensuration is the measurement of shapes: perimeters and areas in 2D, volumes and surface areas in 3D. Learn the area formulas for rectangles, triangles, parallelograms, trapezia and circles, treat arcs and sectors as a fraction (angle/360) of the whole circle, and use the formulas on the exam's formula list for cylinders, cones, spheres and pyramids. Composite shapes are built from these pieces. Cambridge 0580 covers this at both tiers (C5 and E5); Core sectors use angles that are factors of 360°, and Extended adds any sector and frustums. Edexcel 4MA1 Foundation covers circles, prisms and cylinders (4.9, 4.10); Higher adds sectors, cones and spheres. Unit conversions, especially cm^2 to m^2 and cm^3 to litres, are tested on every tier.

Facts checked:

At a glance

Cambridge 0580
Core C5.1 to C5.5; Extended E5.1 to E5.5
Edexcel 4MA1
Foundation 4.9, 4.10; Higher 4.9A, 4.10A
Sector area
(angle/360) × πr^2
Capacity
1 litre = 1000 cm^3

Which formulas are given, and which you must learn

FormulaCambridge 0580 listEdexcel 4MA1 sheet
Area of trapezium 1/2(a + b)hNot givenGiven (both tiers)
Area of triangle 1/2 bhGivenNot given
Circle area πr^2 and circumference 2πrGivenNot given
Volume of prism, cylinderGivenGiven (both tiers)
Curved surface area of cylinder 2πrhGivenGiven (both tiers)
Volume and curved surface area of coneGivenHigher sheet only
Volume and surface area of sphereGivenHigher sheet only
Volume of pyramid 1/3 AhGivenNot given
Arc length and sector areaNot givenNot given

From the Cambridge 0580 List of formulas (Core and Extended) and Edexcel 4MA1 Appendices 4 and 5.

The key ideas

An arc is a fraction of the circumference and a sector is the same fraction of the area. With angle θ, arc length = (θ/360) × 2πr and sector area = (θ/360) × πr^2. The perimeter of a sector is the arc plus two radii, which students often forget.

A prism has the same cross-section all the way through, so its volume is cross-sectional area × length. Cylinders are circular prisms. Pyramids and cones hold one third of the matching prism: V = 1/3 × base area × height. A sphere has V = 4/3 πr^3 and surface area 4πr^2; a hemisphere is half the volume, and its total surface area is half the sphere plus the flat circle.

For a cone, the curved surface uses the slant height l, not the vertical height: curved surface area = πrl, where l = sqrt(r^2 + h^2) by Pythagoras. A frustum (Cambridge Extended) is a cone with its top cut off: subtract the small cone from the large one.

Units scale with the dimension: 1 m = 100 cm, so 1 m^2 = 100^2 = 10 000 cm^2 and 1 m^3 = 1 000 000 cm^3. One litre is 1000 cm^3, so 1 m^3 = 1000 litres. Answers may be asked for 'in terms of π', which means leave π in the answer, for example 24π.

Worked example 1: a sector

  1. A sector has radius 8 cm and angle 135°. Find its arc length, perimeter and area.
  2. Fraction of the circle: 135/360 = 0.375.
  3. Arc length = 0.375 × 2π × 8 = 6π = 18.8 cm (3 s.f.).
  4. Perimeter = arc + two radii = 6π + 16 = 34.8 cm.
  5. Area = 0.375 × π × 8^2 = 24π = 75.4 cm^2. Check: the whole circle is 64π, and 24π is three eighths of it, matching 135/360.

Worked example 2: a cone

  1. A cone has base radius 6 cm and vertical height 8 cm. Find its volume and total surface area, in terms of π.
  2. Volume = 1/3 × π × 6^2 × 8 = 1/3 × 288π = 96π cm^3 (about 302 cm^3).
  3. Slant height l = sqrt(6^2 + 8^2) = sqrt(100) = 10 cm.
  4. Curved surface = πrl = π × 6 × 10 = 60π. Base = π × 6^2 = 36π.
  5. Total surface area = 60π + 36π = 96π cm^2 (about 302 cm^2). The numbers happen to match the volume here, but the units are different.

Worked example 3 (Cambridge Extended): a frustum and a unit conversion

  1. A cone of radius 6 cm and height 12 cm has a cone of radius 2 cm and height 4 cm cut from its top. Find the volume of the frustum.
  2. Large cone: 1/3 × π × 36 × 12 = 144π. Small cone: 1/3 × π × 4 × 4 = 16π/3.
  3. Frustum = 144π - 16π/3 = 432π/3 - 16π/3 = 416π/3 = 435.6..., so 436 cm^3 (3 s.f.).
  4. Unit conversion: a tank measures 1.2 m by 0.8 m by 0.5 m. Its volume is 0.48 m^3, which is 0.48 × 1000 = 480 litres.

Common mistakes that cost marks

  • Using the vertical height instead of the slant height in πrl.
  • Forgetting the two radii in the perimeter of a sector, or the flat circle on a hemisphere.
  • Converting area units with a factor of 100 instead of 10 000 (cm^2 to m^2).
  • Using diameter where the formula needs radius.
  • Rounding π or intermediate values early; use the calculator's π or 3.142 on Cambridge papers.
  • Missing faces when finding the surface area of a prism; list them before adding.

Exam technique and how a tutor helps

Read the first page of the paper: the formula list is there, and knowing what is given saves memorising what you do not need. Cambridge does not give the trapezium formula; Edexcel does. Neither gives arc or sector formulas. When the question says 'in terms of π', keep π as a symbol throughout. On non-calculator papers, expect numbers like radius 6 or angle 120° that simplify cleanly.

For composite shapes, sketch the pieces separately and label each one with its own dimensions before you calculate. Many multi-step questions mix units, such as a length in cm and a capacity in litres, so convert before you calculate.

In one-to-one lessons a tutor can sketch nets and cross-sections on the shared whiteboard, so the student sees which faces or pieces make up a surface area. Lessons then move to the multi-step problems that appear late on papers, such as filling a cylinder from a cone, where the skill is planning the steps rather than recalling a formula.

Self-check: can you do these?

  • Find the area of a trapezium with parallel sides 5 cm and 9 cm and height 4 cm. (Answer: 28 cm^2)
  • Find the volume of a sphere of radius 3 cm. (Answer: 36π = 113 cm^3)
  • Find the circumference of a circle of diameter 10 cm. (Answer: 31.4 cm)
  • Find the volume of a cylinder with radius 2 cm and height 5 cm. (Answer: 20π = 62.8 cm^3)
  • Convert 3.5 m^2 to cm^2. (Answer: 35 000 cm^2)

Common questions

Do I need to memorise the volume of a cone and sphere?

Not for Cambridge 0580, where both are on the list of formulas at Core and Extended. On Edexcel 4MA1 they are on the Higher sheet; Foundation students are not asked for the volume or surface area of cones and spheres.

What does 'give your answer in terms of π' mean?

Leave π as a symbol rather than multiplying it out: for example, 24π cm^2 rather than 75.4 cm^2. It is usually used on non-calculator papers or when an exact answer is wanted.

Is the frustum on the syllabus?

Yes for Cambridge 0580 Extended, which names the frustum in E4.1 and E5.5. The method is to subtract the small cone from the large cone.

How do I convert between cm^3 and litres?

1 litre = 1000 cm^3 and 1 m^3 = 1000 litres. Divide cm^3 by 1000 to get litres.

How much do LiveTutor lessons cost?

Every one-to-one, 60-minute online lesson is $15, at any level. Families choose 1 to 5 lessons a week billed monthly, and the first lesson is a free trial.

Sources

Dates and figures on this page come from these official and published sources. Always confirm deadlines on the official page before acting on them.